Question

The reaction below shows how silver chloride can be synthesized. AgNO3 + NaCl mc017-1.jpg NaNO3 + AgCl How many moles of silver chloride are produced from 15.0 mol of silver nitrate?

Answer 1

The mole ratio of the reaction is AgNO3 + NaCl ⇒NaNO3 + AgCl is

1:1:1:1 This implies that 1 mole of silver nitrate and 1 mole of sodium chloride forms 1 mole of sodium nitrate and 1 mole of silver chloride.

Thus the moles of silver chloride to be produced from 15 mole of silver nitrate is 15 moles.

Answer 2

Answer: 15 moles of silver chloride will be produced in the given reaction:

Explanation: The given reaction follows:

$AgNO_3+NaCl\rightarrow NaNO_3+AgCl$

By stoichiometry of the reaction,

1 moles of silver nitrate produces 1 mole of silver chloride

So, 15.0 moles of silver nitrate will produce = $\frac{1}{1}\times 15.0$ = 15.0 moles of silver chloride.