Chemistry, asked by demigod15, 10 months ago

the reaction,NH2CN(s) +3/2O2(g) -->N2(g) + CO2(g) + H2O(l) was carried out in a bomb caloriemeter . the heat released wqs 743kj/mol. the value of ∆H300k for this reaction would be?​

Answers

Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
0

Answer:

The reaction of cyanamide, NH2CN (s), with dioxygen was carried out in a bomb calorimeter, and ∆U was found to be –742.7 kJ mol–1 .

Answered by Somayayadav01
0

Answer:

The reaction of cyanamide, NH2CN (s), with dioxygen was cerried out in a bomv calorimeter, and triangleU was found to be ‐742.7 kl mol—1.

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