Question

The reaction of bromine with warm NaOH(aq) produces products with the same oxidation numbers, in the same ratios, as the reaction of chlorine with hot NaOH(aq). In one reaction between bromine and warm NaOH(aq), 30.2 g of a product containing sodium, bromine and oxygen is produced. Which mass of NaOH has reacted?

i want the method please.

Answer 1

Answer:

48grams

Explanation:

The reaction between sodium hydroxide and bromine produces water , sodium bromate , sodium bro

Sodium bromide ,and water according to the equation below.

3Br2 +6 NaOH ⇒ 5NaBr + NaBrO3 + 3H2O

Since we have the mass of bromate (NaBrO3) we can get the moles

Moles ; mass ÷ molar mass

Molar mass ⇒ 23 + (16 × 3) + 79.904 = 150.904

30.2 ÷ 150.904 = 0.20 moles

NaOH and sodium bromate react in the ratio 6 : 1 therefore we take the moles of sodium bromate

multiply by six

0.2 × 6 = 1.2 moles of sodium hydroxide

To get the mass we take the moles multiply by the molar mass

Molar mass; 23 + 16 + 1 = 40

40 × 1.2 = 48 grams.

Answer 2

Explanation:

$\huge \tt 48 \: grams$