The reaction of copper sulphate, sodium carbonate, and glucose is an oxidation-reduction reaction. Glucose is an example of reducing sugar. A reducing sugar contains an aldehyde group, which can oxidize the cupric ion (Cu2+) to cuprous ion (Cu+). The cuprous ion then forms the red precipitate, copper (I) oxide (Cu2O) due to the presence of carbonate ion in the solution.
How do I write an ionic equation for this reaction? Thank you in advance!
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Write the molecular equation and balance it. Mg + 2 HCl MgCl2 + H2
Determine the state of each substance (gas, liquid, solid, aqueous). ...
Write the ionic equation by breaking all the soluble ionic compounds (those marked with an (aq)) into their respective ions.
An ionic equation is a chemical equation where the electrolytes in aqueous solution are written as dissociated ions. Example: 1) Sodium chloride(aq) + silver nitrate(aq) → silver chloride(s) + sodium nitrate(aq) >>Ag+(aq) + Cl-(aq) → AgCl(s) 2) Sodium(s) + hydrochloric acid(aq) -> sodium chloride(aq) + hydrogen(g).
Explanation:
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