Question

The reaction of potassium superoxide, KO2, is used in life-support systems to replace CO2(g) in expired air with O2(g). 4KO2(s)+2CO2(g)→2K2CO3(s)+3O2(g).
How many moles K2CO3 are produced per milligram of KO2 consumed?

Answer 1

Answer:

4KO

2

+2H

2

O→3O

2

+4KOH

4 moles of KO

2

→ 3 moles of O

2

molar mass of KO

2

= 71 g/mol

molar mass of O

2

= 32 g/mol

Mass of KO

2

=

3×32

4×71

×48 = 142 g

Explanation:

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Answer 2

$\huge\sf\fbox\purple{ ♡ Solution ♡ }$

★ Explanation ★

3 KO 2 +2H 2 →3O 2 +4KOH

4 moles of KO 2 → 3 moles of O 2

molar mass of KO 2 = 71 g/mol

molar mass of O 2

= 32 g/mol

Mass of KO 2

=

3 × 32 , 4 × 71

× 48 = 142 g