Chemistry, asked by mohasnh8, 6 months ago

The reaction out in a laboratory reactor. According to a published article t concentration of A should vary with time as follows: CA-CAO Cxp(-hp) where CAo is the initial concentration of A in the reactor and k is a constant. (a) If CA and CAO are in Ib-moles/ft' and r is in minutes, what are the units of (b) The following data are taken for CA(1):

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Answered by hkemem200
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Answer:

The reaction A\rightarrow B is carried out in a laboratory reactor. According to a published

article the concentration of A should vary with time as follows:

CA= CAo*exp(-kt)

where CAo is the initial concentration of A in the reactor and k is a constant.

(a) If CA and CAo are in lb-moles/ft3 and t is in minutes, what are the units of k?

(b) The following data are taken for CA(t):

t(min): 0.5 , 1.0 , 1.5 , 2.0, 3.0, 5.0 , 10.0

CA (lb-mole/ft3): 1.02 , 0.84 , 0.69 , 0.56 , 0.38 , 0.17 , 0.02

Verify the proposed rate law graphically ( first determine what plot should yield a

straight line), and calcualte CAo and k.

(c) Convert the formula with calculated constants included to an expression for the mo-

larity of A in the reaction mixture in terms of t (seconds). Calculate the molarity at

t = 265 s.

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