Question

the reaction Pcl5=Pcl3+cl2 is started in a five liter container by taking one mole of pcl5. if 0.3 mole of Pcl5 is there at equilibrium concentration of pcl3 and kc will respectively be​

Answer 1

Answer:

   PCl5     ---------->         PCl3         +        Cl2

t=0                 0.4                             0                        0

t=teq.           0.4-x                            x                         x

At eqm., (0.4 -x) = 0.65*0.4

Or

x = 0.4 – 0.4*0.65

   =0.4(1-0.65)

   =0.4*0.35

   = 0.14

 

Kc = 0.14*0.14/0.26  

     = 0.0753846

please mark it as a brainalist answer