The reaction time for an automobile driver
is 0.7 sec. If the automobile can be
decelerated at 5 m/s2 calculate the total
distance travelled in coming to stop from an
initial velocity of 8.33 m/s after a signal is
observed.
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Answer:
Given,
Initial velocity (u) = 8.33m/s
Accleration (a) = 5m/s^2
Time (t) = 0.7sec
To find:-
Distance
By applying, S = ut+1/2at^2
= 8.33×0.7+1/2×5×0.49
= 5.831+1.225
= 7.056m.
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