the reaction time of an automoblie is 0.7 sec.if the automobile can be decelerated at 5 m/s^2 calculate the total distance travelled in coming to stop from an initial velocity of 8.33 m/s after a single is observed.
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Firstly time taken to stop,
v=u+at
since car has stopped ,v=0
0=8.33+(-5)(t)
8.33=5t
t=5.66sec
total time = reaction time + time calculated
total time = 5.66+0.7
=6.36sec
now,s=ut+1/2 a t^2
s=8.33+1/2×5×6 .36×6.36
s=28.3728m
v=u+at
since car has stopped ,v=0
0=8.33+(-5)(t)
8.33=5t
t=5.66sec
total time = reaction time + time calculated
total time = 5.66+0.7
=6.36sec
now,s=ut+1/2 a t^2
s=8.33+1/2×5×6 .36×6.36
s=28.3728m
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