Question

the reaction with t0.5 =69.3 and rate constant is 10-2 then order is

Answer 1

$\large\underline{\bigstar \: \: {\sf Question-}}$

The reaction with ${\sf t_{1/2}=69.3}$ and rate constant is 10-2 then order is

$\large\underline{\bigstar \: \: {\sf Answer-}}$

It is First Order Reaction

$\large\underline{\bigstar \: \: {\sf Solution-}}$

Reaction in which the rate of reaction depends only on one concentration term of reactant is first order reaction.

$\underline{\bigstar \: \: {\rm Half \: life \: for \: first \: order \: reaction-}}$

$\color{violet}\bullet\underline{\boxed{\sf t_{1/2}=\dfrac{0.693}{K}}}$

Let say we don't know that value of ${\sf t_{1/2}}$

then ,

$\implies{\sf t_{1/2}=\dfrac{0.693}{10^{-2}}}$

$\implies{\sf t_{1/2}=0.693×10^2 }$

$\implies{\sf t_{1/2}=69.3\:s }$

And we got the given value of half life i.e. 69.3 s

Hence , this is $\color{red}{\sf First \: Order \: Reaction}$