Physics, asked by nehachinnukudum, 1 year ago

The reading corresponding to the ice points and steam points for a constant pressure gas thermometer are 50cc if the corresponding to room temperature be 510cc find the room temperature

Answers

Answered by mannatmarya
3

(x-20)/(80-20) =(C-0)/(100-0)


(x-20)/60=(C-0)/100


now question given ,

x=32

then ,

(32-20)/60=(C-0)/100


12/60=C/100

C=20 degree


hence in centigrade thermometer 20 degree

Answered by Princess1234567
2

(x-20)/(80-20) =(C-0)/(100-0)



(x-20)/60=(C-0)/100



now question given ,


x=32


then ,


(32-20)/60=(C-0)/100



12/60=C/100


C=20 degree



hence in centigrade thermometer 20 degree...

Plzz mark me as brainliest my dear...

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