the reading of a solution in a beaker is 200 ml but it was read as 280 find the percent error
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Answered by
3
Error is true value-measured value=200-280=-80
percentage error=error/real value×100
-80/280×100=-14.28%
ShouryaKothari:
It is wrong
-80/200×100=-40%
-80/200×100=-40%
Answered by
8
Answer:
READING OF SOULTION IN BEAKER = 200ML
ERROR READING SHOWN BY IT = 280ML
ERROR SHOWN = 280 - 200 = 80ML
Step-by-step explanation:
ERROR PERCENTAGE = 80 × 100 /200
= 40 %
ERROR PERCENTAGE IS 40%
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