Question

the reading of the ammeter is 3.0A find the current through 10 ohm and 20 ohm resistors

Answer 1

LET THE 10 OHM RESISTOR BE R1 AND 20 OHM RESISTOR BE R2.

LET THE CURRENT IN 10 OHM RESISTOR BE I1
AND CURRENT IN 20 OHM RESISTOR BE IN
READING OF AMMETER BE I.

.: I = 3.0 OHM

I1 = IR2 ÷ R1 + R2
= 3×20 ÷ 10 +20
=60 ÷ 30
= 2 A
.: CURRENT FLOWING THROUGH R1 IS 2 AMPERE.

I2 = IR1 ÷ R1 + R2
= 3 × 10 ÷ 10 +20
= 30 ÷ 30
= 1 A
.: CURRENT FLOWING THROUGH R2 IS 1 AMPERE.

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