Question

The readingo 14 and is of two thermometer of A and B agree at ice point and steam point and related by equation tA= m tB +n to? + L between these temperature warm
and n are constant both are immersed in oil A reads 51°C and Breads 50°C. Determine the reading on A When Breads 25°C. Discuss which thermometer is corred​

Answer 1

Explanation:

tA=l+mtB+n(tB)²

According to question

tA=tB=0°C

tA=l+mtB+n(tB)²

0=l+0+0

l=0

Second step

tA=tB=100°C

tA=l+mtB+n(tB)²

100=0+m×100+n(100)²

m+100n=1 ----------------------------(1)

For

tA=51°C

tB=50°C

tA=l+mtB+n(tB)²

51=0+M50+n(50)² -----------------------------(2)

Now using equation (1) and (2) find m&n

50m+2500n=51

50m+5000n=50

- - -

________________

0 -2500n=1

n=-1/2500

Put value of 'n' in equation (1)

m+100×(-1/2500)=1

m=26/25

At tB=25°C, l=0

tA=mtB+n(tB)²

=26/25×25-1/2500×25×25

=26-1/4

tA=25.75°C

tB=25°C