The real function F(x) = [x] 1 point %3D .where x is real number and [x] denotes greatest integer fnction is
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Answer:
Let f(x)=∣[x]x∣ for −1≤x≤2 , where [x] denotes greatest integer function, then
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We divide the interval in 4 parts,
For −1<x<0
f(x)=−x
For 0<x<1
f(x)=0
For 1<x<2
f(x)=x
For x=2
f(x)=4
Now at x=0,
lim x →0
−
f(x) = 0 = lim x →0
+
f(x)
Hence, f(x) is continuous at x = 0
At x = 1
lim x →1
−
f(x) = 0 not equal to lim x →1
+
f(x)
Hence, f(x) is discontinuous at x = 1
At x = 2
lim x →2
−
f(x) = 0 not equal to lim x = 2 f(x)
Hence, f(x) is discontinuous as well as non-differentiable at x=2
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Answered by
1
Answer:
Given, [x]
2
+2[x]=3x
Case 1. when 0≤x<1⇒[x]=0
∴3x=0+0⇒x=0
Case 2. when 1≤x<2⇒[x]=1
∴3x=1+2⇒x=1
Case 3. when x=2⇒[x]=2
∴3x=2
2
+2.2=8⇒x=8/3
=2
Hence solution is {0,1}
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