Question

the real image of an object placed in focal length 12cm formed at a point which is 10cm more distant from the mirror than the object the magnification of image is​

Answer 1

Answer:

Step-by-step explanation:

We have: 1f=1u+1v

Given: f=12 cm and v=u+10

⟹112=1u+1u+10

⟹u=20 cm

⟹v=20+10=30 cm

We have magnification, m=vu=3020=1.5