The real number k for which 2x3+3x+k=0 has two distinct real roots
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Answered by
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f(x) = 2x^3+3x+k
f′(x) = 6x^2+3
f′(x) = 0
x^2 = -1/2
Not Possible.
As condition for two distinct real root is = 0
plzz mark as brainliest answer !!!
f′(x) = 6x^2+3
f′(x) = 0
x^2 = -1/2
Not Possible.
As condition for two distinct real root is = 0
plzz mark as brainliest answer !!!
Answered by
8
Given equation :- 2x² + 3x + k = 0
• When the quadratic equation have distinct real roots then the discriminant will be greater than Zero .
i.e, D > 0
And
D = b² - 4ac
So, here ,
b² - 4ac > 0
( 3 )² - 4 × 2 × k > 0
9 - 8k > 0
9 > 8k
9/8 > k
The value of k will satisfy the equation only when the value is less than 9/8
• When the quadratic equation have distinct real roots then the discriminant will be greater than Zero .
i.e, D > 0
And
D = b² - 4ac
So, here ,
b² - 4ac > 0
( 3 )² - 4 × 2 × k > 0
9 - 8k > 0
9 > 8k
9/8 > k
The value of k will satisfy the equation only when the value is less than 9/8
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