Question

The real part of
(1+1)2
- is
3-i​

Answer 1

Answer:

What is the real part of ((1+i) ^2) /(3-i)?

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Let z= (1+i)23−i=1−1+2i3−i

Using (a+b)2=a2+b2+2ab

⟹2i3−i

Multiply by 3+i3+i

2i(3+i)9+1(using (a+b)(a-b) =a2−b2)

=6i−210=−15+3i5

so, R(z)=−15

Step-by-step explanation:

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