Question

The real root(s) of the equation 9^x - 10(3^x ) + 9 = 0 are​

Answer 1

Answer:

9^x - 10(3^x)+9=0

or, 3^2x - 10(3^x)+9=0

putting 3^x= p , we get,

p²-10p+9=0

or, p²-9p-p+9=0

or, p(p-9)-(p-9)=0

or, (p-9)(p-1)=0

or, p= 9 or 1

or, 3^x=9 or 1 = 3² or 3⁰

or, x = 2 or 0