the rectangle at the corner measures 10cm ×20cm. the corner A of the rectangle is also a point om the circumference of the circle. find the radius of the circle.
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50
Step-by-step explanation:
Given the rectangle at the corner measures 10 cm ×20 cm. the corner A of the rectangle is also a point om the circumference of the circle. find the radius of the circle.
We are given 10 and 20. So we can take as x – 10 and x – 20
Now (x – 20)^2 + (x – 10)^2 = x^2
So x^2 – 40 x + 400 + x^2 – 20 x + 100 = x^2
Now x^2 – 60 x + 500 = 0
So x^2 – 50 x – 10 x + 500 = 0
x (x – 50) – 10 (x – 50) = 0
(x – 10) (x – 50) = 0
So x = 10 , 50
Now since x cannot be 10, x = 50
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