Question

The rectangle box has dimensions as shown. What is the length AG?

Answer 1

Answer:

$\sqrt{16}$

Answer 2

Answer:

$2\sqrt{26}$

Step-by-step explanation:

GIVEN:

l = 6 cm

w = 8 cm

h = 2 cm

FORMULA TO USE:

d = $\sqrt{l^{2} + w^{2} + h^{2} }$

SUBTITUTE VALUES:

d = $\sqrt{6^{2} + 8^{2} + 2^{2}}$

SOLVE:

d = $\sqrt{36 + 64 + 4 }$

d = $\sqrt{104}$

(*Find a factor where one of them has a square root, in this case 4*)

d = $\sqrt{4 (26)}$

(*Isolate the square root and move it outside*)

d = $\sqrt{2^{2} (26) }$

d = $2\sqrt{26}$