The rectangle has sides of length 10.3 cm and 6.7cm, correct the nearest millimeter.
found the lower and upper bounds of the are of the rectangle
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2
Answer:
Here, l=(5.7±0.1)cm,b=(3.4±0.2)cm
Area, A = l×b=5.7×3.4=19.38cm
2
=19.0cm
2
(rounding off to two significant figures)
∴
A
△A
=±(
l
△l
+
b
△b
)
= ±(
5.7
0.1
+
3.4
0.2
)=±(
5.7×3.4
0.34+1.14
)=±
19.38
1.48
⇒△A=±
19.38
1.48
×A=±
19.38
1.48
×19.38=±1.48
△A=±1.5 (rounding off to two significant figures);
Area = (19.0±1.5)cm
2
.
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