Question

The rectangle is given A=6x^2y+4y^2x and the width of rectangle is w=2xy what is the perimeter of the rectangle ?​

Answer 1

Answer:

perimeter = 6x + 4y + 4 xy

Step-by-step explanation:

A = w * l

w = 2xy

A=6x^2y+4y^2x = 2xy * l

l = (6x^2y+4y^2x) / 2xy

l = 3x + 2y

perimeter = 2 * ( w + l ) = 2 ( 2xy + 3x + 2y ) = 6x + 4y + 4 xy

Answer 2

Answer:-

6x+4y+4xy

Given:-

Area of rectangle= 6x^2y+4y^2x

width= 2xy

Explanation:-

Area of rectangle=l×b

6x^2y+4y^2x=l×2xy

l=6x^2y+4y^2x/2xy

l=2xy(3x+2y)/2xy

l=3x+2y

perimeter of rectangle=2(l+b)

=2(3x+2y+2xy)

=6x+4y+4xy