the rectangle length is 5 cm than twice its with if length is decreased by 5 cm and weight is increased by 2 metre the perimeter of resulting rectangle will be 74 find the Length and width of original rectangle
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let the length be as x cm
let the width be as y cm
then according to the condition
x=2y-5
as the perimeter of rectangle is 2( l+b )
then 2( x+y )
then 2( x-5 + y+2 )=74
from first condition
2( 2y-5-5 + y+2 )=74
2( 3y-8 )=74
3y-8=74/2
3y-8=37
3y=45
y=15
and
x=25
hence length and width found dude
let the width be as y cm
then according to the condition
x=2y-5
as the perimeter of rectangle is 2( l+b )
then 2( x+y )
then 2( x-5 + y+2 )=74
from first condition
2( 2y-5-5 + y+2 )=74
2( 3y-8 )=74
3y-8=74/2
3y-8=37
3y=45
y=15
and
x=25
hence length and width found dude
kHarsh1:
thankd
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