Question

The rectangle of a length 16 cm more than its breadth is same in area as the square of side 15 cm . find the sides of rectangles​

Answer 1

area of square= (15)^2 = 225cm

area of square= area of rectangle

therefore , area of rectangle= length*breadth=l*b

therefore l*b=225 cm

16*b= 225

b= 225/16

b=14.0625

=14.0cm(approx.)

therefore, breadth= 14cm(approx )

Hope this is helpfull

Answer 2

let breadth of rectangle be b

so length equals b+16

area of rectangle is b(b+16) length x breadth

area of square of side 15cm = 225cmsq sidexside

so they gave area as same

225=b(b+16)

225=b^2+16b. (^means power)

b^2+16b-225=0

by quadadric formula

b = [-16±root(16^2-4(1)(-225))]÷2(1)

b= [-16±root(256+900)]÷2

b=[-16±root(1156)]÷2

b=[-16±34]÷2

since breadth cant be negative

b= (34-16)/2 = 18/2

b= 9cm and as we know length equals 16+b

length of rectangle is 25cm.

CHEERS DUDE