the rectangle of length 16 cm more than its breadth is same in area of square of side 15 cm.Find the sides of rectangle.
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Side of square = 15 cm.
Area of square = (Side)²
=> (15)² = 225 cm².
Let Breadth of rectangle be X cm.
Given that : Length of rectangle is 16 cm more than the breadth of rectangle .
Therefore,
Length of rectangle = ( X + 16 ) cm.
According to question,
Area of rectangle = Area of square
Length × Breadth = 225
( X + 16 ) X = 225
X² + 16X - 225 = 0
X² + 25X - 9X - 225 = 0
X ( X + 25 ) - 9 ( X + 25 ) = 0
( X + 25 ) ( X - 9 ) = 0
( X - 9 ) = 0 OR ( X + 25 ) = 0
X = 9 OR X = -25.
Since , side can't be in negative , so x = 9 cm.
Breadth of rectangle = X = 9 cm.
And,
Length of rectangle = X + 16 = 25 cm
Area of square = (Side)²
=> (15)² = 225 cm².
Let Breadth of rectangle be X cm.
Given that : Length of rectangle is 16 cm more than the breadth of rectangle .
Therefore,
Length of rectangle = ( X + 16 ) cm.
According to question,
Area of rectangle = Area of square
Length × Breadth = 225
( X + 16 ) X = 225
X² + 16X - 225 = 0
X² + 25X - 9X - 225 = 0
X ( X + 25 ) - 9 ( X + 25 ) = 0
( X + 25 ) ( X - 9 ) = 0
( X - 9 ) = 0 OR ( X + 25 ) = 0
X = 9 OR X = -25.
Since , side can't be in negative , so x = 9 cm.
Breadth of rectangle = X = 9 cm.
And,
Length of rectangle = X + 16 = 25 cm
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0
Answer:
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Explanation:
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