The rectangle of side 8cm and 6cm is inscribed inside the circle find the remaining area of the circle
Answers
Answer:
The remaining area of the circle is 30.54 sq. cm.
Step-by-step explanation:
The dimensions of rectangle are 8 cm and 6 cm.
The area of rectangle is
The area of rectangle is 48 sq. cm.
The diagonal of rectangle is diameter of circle.
The diameter of circle is 10. so the radius is 5 cm.
Area of circle is
The area of circle is 78.54 sq.cm.
The remaining area of the circle
Therefore the remaining area of the circle is 30.54 sq. cm.
Answer:
30.5 cm²
Step-by-step explanation:
Length of the rectangle=8 cm
Breadth of the rectangle=6 cm
Area = length*breadth
Area = 8*6 = 48 cm²
We know, that the diagonal of the rectangle is the diameter of the circle.
That particular diagonal divides the rectangle into 2 congruent right triangles.
So, by Pythagoras Theorem,
8²+6²=diagonal²
⇒36+64 = d²
⇒d=√100
⇒d = 10 cm
Now, the diameter of the circle is 10 cm. So, the radius of the circle = 10/2 = 5 cm.
Area of the circle = πr²
= 3.14*5*5
= 78.5 cm²
Area of the remaining part of the circle = area of the circle - area of the rectangle.
Area of the remaining part of the circle = 78.5 - 48
Area of the remaining part of the circle = 30.5 cm².