Question

The rectangle pqrs alongside is the map of land using the given measures.Find it's area. Ps=60cm,pq=11cm,sr=10cm

Answer 1

Area of rectangle is L*B

if we take PQ as B,

we get area 660cm²

if we take SR as B,

we get area 600cm²

Answer 2

Answer:

Step-by-step explanation:

Answer:

By Pythagoras Theorem for Δ PQS

$(QS)^{2} = (PS)^{2} + (PQ)^{2} \\(QS)^{2} = (60)^{2} +(11)^{2} \\(QS)^{2} = 3600 + 121\\(QS) = \sqrt3721\\(QS) = 61$

By Pythagoras Theorem for Δ SQR

$(SR)^{2} = (QR)^{2} + (SR)^{2} \\(61)^{2} = (QR)^{2} + (10)^{2} \\3761 = (QR)^{2} + 100\\(QR)^{2} = 3761 - 100\\(QR)^{2} \sqrt{3661} \\(QR) = 60.174$

Area of Δ PQS = $\frac{1}{2}$ × $b$ × $h$

                        = $\frac{1}{2}$ × $60$ × $11$

                        = $30$ × $11$

                        = $330$ sq. cm.

Area of Δ SQR = $\frac{1}{2}$ × $b$ × $h$

                        = $\frac{1}{2}$ × $60.174$ × $10$

                        = $10$ × $60.174$

                        = $300.87$ sq. cm.

Area of Quadrilateral PQRS = Area of Δ PQS + Area of Δ SQR

                                              = $330 + 300.87$

                                              = $630.87$ sq. cm.