Question

The rectangle shown has a perimeter of 102 cm and the given area. Its length is 6 more than four times its width. Write and solve a system of equations to find the dimensions of the rectangle.

Answer 1

Answer:

Step-by-step explanation:

let width be x

so length=6+4x

p=2(l+b)

102=2(x+6+4x)

     =2(6+5x)

102=12+10x

102-12=10x

90=10x

x=9

so length=6+36=42 cm

width=9 cm

hope it helps:)

Answer 2

Answer:

9x

Step-by-step explanation:

let width will be x

length x+6+4x

x+6+4x =10x - x = 9 x