Math, asked by navya3333, 1 year ago

the rectangular field is 15 metre long and has 10 m wide another rectangle field has the same perimeter has its sides in the ratio 4 :1 find the dimension pf the rectangular field​

Attachments:

Answers

Answered by sreejansneh74
5

Perimeter of 1st rectangle= 2(15+10)

= 2* 25

= 50 m

given, 2nd rectangle perimeter = 50 m

let the length of the 2nd rectangle be 4x and breadth be 1x or x

ATQ,

=2(4x+x) = 50

=> 2*5x = 50

=> 5x = 50/2

=> x = 25/5

=> x = 5

therefore , the dimensions of the rectangle are : length = 4x or 4*5 = 20 m

= x or 5m

HOPE IT HELPS U


navya3333: thanks and your name plz
Answered by aditya12934
0

I hope that you are satisfied now

Attachments:

aditya12934: did you had under stooded now
navya3333: no
aditya12934: whats the problem where did you not understand
navya3333: how sum will get that my problem
navya3333: ok why are shouting at me
aditya12934: the side of other triangle has taken as 4xand xthen i habe applied the formulaof perimeter
navya3333: now understand
aditya12934: i am not shouting on you
aditya12934: ok
navya3333: good friend
Similar questions