Question

The rectangular frame of a picture is 24.5 cm wide and 36.6 cm high. The border is 3.4 cm wide calculate the perimeter of the pictures

Answer 1

Therefore, the perimeter of the picture will be 95cm.

Answer 2

The perimeter of the picture is 95 cm.

------------------------------------------------------------------------------------

Let's understand a few concepts:

To calculate the perimeter of the picture we will use the following formula for the perimeter of a rectangle:

$\boxed{\bold{Perimeter\:of\:rectangle = 2 [length + breadth]}}$

----------------------------------------------------------------------------------

Let's solve the given problem:

The width of the rectangular frame (w) = 24.5 cm

The length of the rectangular frame (l) = 36.6 cm

The width of the border of the rectangular frame = 3.4 cm

Therefore,

The width of the picture will be = 24.5 - (2 × 3.4) = 24.5 - 6.8 = 17.7 cm

and

The length of the picture will be = 36.6 - (2 × 3.4) = 36.6 - 6.8 = 29.8 cm

Now, by using the above formula for the perimeter of a rectangle, we get

The perimeter of the picture is,

= Perimeter of a rectangle

= $2\times [length + width]$

= $2\times [29.8 + 17.7]$

= $2\times 47.5$

= $\bold{95 \:cm}$

Thus, the perimeter of the picture is 95 cm.

#SPJ3

--------------------------------------------------------------------------------------

Learn more from brainly.in:

brainly.in/question/38760918

brainly.in/question/39027703?msp_poc_exp=2