The rectangular garden has an area of 48 m 2 and perimeter 28m.what is the length of it's diagonal
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l×b=48
2l+2b=28
l=48/b
put this in above equation
2×48/b + 2b =28
b=6m
put this in upper equation
l=48/6
l=8m
using Pythagoras
we obtain length of its diagonal =10m
2l+2b=28
l=48/b
put this in above equation
2×48/b + 2b =28
b=6m
put this in upper equation
l=48/6
l=8m
using Pythagoras
we obtain length of its diagonal =10m
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