Question

The rectangular hall has a length of 12 meters and a width of 6 meters. This room has to fit square fences with a width of 30 cm; How many fishes will be sitting in the entire hall? If you take a squared furrow in front of this example 15 cm, how much tangarasera?

Answer 1

Given data :

  • length of the hall = 12 m

  • width of the hall = 6 m

Solution :

Thus, the area of the hall

= length of the hall * width of the hall

  = 12 * 6 m²

     = 72 m²

        = 72 * 10000 cm²

           = 720000 cm²

Case 1 ( square fences with 30 cm width ) :

Width of a square fence = 30 cm

Area = width² = 30² cm² = 900 cm²

Thus, required number of fences

  = $\dfrac{\text{Area of the hall}}{\text{Area of each fence}}$

     = $\dfrac{720000}{900}$

        = 800

Case 2 ( square fences with 15 cm width ) :

Width of a square fence = 15 cm

Area = width² = 15² cm² = 225 cm²

Thus, required number of fences

  = $\dfrac{\text{Area of the hall}}{\text{Area of each fence}}$

     = $\dfrac{720000}{225}$

        = 3200

Case 3 ( square fences with added width ) :

Width of a square fence

  = 30 + 15 cm

     = 45 cm

Area = width² = 45² cm² = 2025 cm²

Thus, required number of fences

  = $\dfrac{\text{Area of the hall}}{\text{Area of each fence}}$

     = $\dfrac{720000}{2025}$

  = 356 ( nearly )