Math, asked by prameelakv71, 5 months ago

The red king card are removed from a pack of 52cards and a card is drawn at random from the remaining card. Find the probilit that the card darwn is
1. A queen
2. A red card

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Answered by saba1257
1

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Red queens and black jacks are removed from a pack of 52 playing cards.A card is drawn at random from the remaining cards, after reshuffling them. Find the probability that the drawn card is

(i) a king

(ii) of red color

(iii) a face card

(iv) a queen

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ANSWER

2 red queens and 2 black jacks are removed from a pack of 52 cards.

So, cards remaining are 48.

∴n(S)=48

We need to find probability that 1 card drawn at random is

(1) a king

There are 4 kings in a pack.

Let A be the event of drawing a king.

∴n(A)=4

Therefore probability of drawing a king from 48 remaining cards is

P(A)=

n(S)

n(A)

P(A)=

48

4

=

12

1

(2) of red colour

After removing 2 red queens, there remain 24 red colour cards in a pack.

Let B be the event of drawing a red colour card from remaining 48 cards.

∴n(B)=24

Therefore probability of drawing a red colour card is

P(B)=

n(S)

n(B)

P(B)=

48

24

=

2

1

(3) a face card

2 red queen and 2 black jacks are removed from a pack. Therefore, total face cards remaining are 8.

Let C be the event of drawing a face card.

∴n(C)=8

Therefore probability of drawing a face card is

P(C)=

n(S)

n(C)

P(C)=

48

8

=

6

1

(4) a queen

There are remaining only 2 queens after removing 2 red queens.

Let D be the event of drawing a queen.

∴n(D)=2

Therefore probability of drawing a queen is

P(D)=

n(S)

n(D)

P(D)=

48

2

=

24

1

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