The red king card are removed from a pack of 52cards and a card is drawn at random from the remaining card. Find the probilit that the card darwn is
1. A queen
2. A red card
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Red queens and black jacks are removed from a pack of 52 playing cards.A card is drawn at random from the remaining cards, after reshuffling them. Find the probability that the drawn card is
(i) a king
(ii) of red color
(iii) a face card
(iv) a queen
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ANSWER
2 red queens and 2 black jacks are removed from a pack of 52 cards.
So, cards remaining are 48.
∴n(S)=48
We need to find probability that 1 card drawn at random is
(1) a king
There are 4 kings in a pack.
Let A be the event of drawing a king.
∴n(A)=4
Therefore probability of drawing a king from 48 remaining cards is
P(A)=
n(S)
n(A)
P(A)=
48
4
=
12
1
(2) of red colour
After removing 2 red queens, there remain 24 red colour cards in a pack.
Let B be the event of drawing a red colour card from remaining 48 cards.
∴n(B)=24
Therefore probability of drawing a red colour card is
P(B)=
n(S)
n(B)
P(B)=
48
24
=
2
1
(3) a face card
2 red queen and 2 black jacks are removed from a pack. Therefore, total face cards remaining are 8.
Let C be the event of drawing a face card.
∴n(C)=8
Therefore probability of drawing a face card is
P(C)=
n(S)
n(C)
P(C)=
48
8
=
6
1
(4) a queen
There are remaining only 2 queens after removing 2 red queens.
Let D be the event of drawing a queen.
∴n(D)=2
Therefore probability of drawing a queen is
P(D)=
n(S)
n(D)
P(D)=
48
2
=
24
1