Chemistry, asked by qanita11, 10 months ago

The reduction of alkyl halides takes place in the presence of
(A) Zn/HCI
(B) Na/HCI
(C) Mg/HCI
(D) Cu/HCI

Answers

Answered by ItzSmartyYashi
2

\huge{\underline{\mathbb{\red{Answer}}}}

C) Mg/HCI

______________________________________

\huge{\underline{\underline{\mathfrak{Thank you}}}}

Answered by SmritiSami
0

The reduction of alkyl halides takes place in the presence of Zn/HCI. (Option A)

  • Alkanes are formed when alkyl halides (excluding fluorides) are reduced with zinc dilute hydrochloric acid.
  • The reductive dehalogenation of alkyl halides, in which the halogen atom is substituted by a hydrogen atom in the vicinity of proton donors such as carboxylic acids or water, is a key reaction of activated zinc.
  • As a result, option A is the proper response to the question.
Similar questions