Question

The reference line in the screw gauge is coinciding with division 96 in the circular scale initially. Then the zero error is what ?​

Answer 1

Explanation:

let the main scale reading=0cm

circular scale reading =least count * no. of division coinciding with the index line

circular scale reading=0.01 * 96

circular scale reading=0.96cm

now ,zero error =main scale reading +circular scale reading

zero error=0+0.96

zero error =0.96cm