Question

The refracting angle of a prism is 40°. A ray of
light is incident at angle 38° and passes in the
position of minimum deviation. The angle of
minimum deviation is-
(1) 40° (2) 38° (3) 36° (4) 32°​

Answer 1

Answer:

36

Explanation:

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Answer 2

Answer:

angle of prism A is 30

angle of incidence is 60 degree

angle of deviation is 30 degree

i

1

+i

2

=A+δ

the angle of emegrance

i

2

=A+δ−i

1

=30+30−60=0

'the emergent ray

r

1

+r

2

=Ai 2 =0,r 2 =0 r 1 =A=300

using snells law

n= sinr 1 sini 1 =sin30sin60 =1.732

since emergent ray is normal

δ=δ m=300

sin30/2sin(30+30/2) =1.732

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