Question

The refracting angle of the prism having refractive index 1.5 is 60. what is the angle of emergence when it suffers maximum deviation.​

Answer 1

Answer:here R.I= 1.5

A=60 degree

so r= A/2

60/2=30

R.I= sin i/sin r

1.5= sin i/sin 30

sin i= 1.5*0.5= 0.75

i= sin^-1(0.75)

= 48.6 degree

angle of deviations= 2i - A

2*48.6-60

=37.2 degree

Explanation: