The refractive index and radius of curvatures of lens are given as 1.5, 30 cm and -35 cm respectively. find the focal length of the lens. (hint: lensmaker's equation)
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Given,
- Radius of curvatures of lens are 1.5 ,30 cm and -35 cm
To Find:-
- Find the focal length of the lens.
Calculations:-
- (n-1)(1/R1 - 1/R2)--> Lens makers formula.
according to the question,
The given values are.
n=1.5
R1 = 30
R2 = -35
=(1.5-1)(1/30-1/-35)
= (0.5)(1/30 - 1/-35)
using the formula 1/f
= 1/12
f = 12 cm
Thus ,the focal length of the lens is 12cm.
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-Happies!!
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