Chemistry, asked by anana1200, 10 months ago

The refractive index n of ch2i2 is 1.732 for 656 nm light. Its density at 20c is 3.32 g.Cm?. Calculate the distortion polari

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Answered by sourya1794

Explanation:

The refractive index n of CH2I2 is 1.732 for 656 nm light. Its density at 20°C is 3.32 g.cm?. Calculate the distortion polarizability a, (in units of J-'.C.m) of the molecule at this wavelength.

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