Question

the refractive index of a material of a Plano convex lens is 5 by 3 the radius of curvature is 0.3 metres the focal length of the length in air

Answer 1

$focal \: length \: of \: lens \: will \: be \: \: half \: of \: radius \: of \: curvature \\ so \\ \\ f = \frac{ \ \: r}{2} \: \\ f = \frac{30 \: cm}{2} \\ f = + 15cm \: \\ \: \: \: \: \: \: \: \: \: hope \: it \: will \: help \: you \: \\ \: \: mark \: as \: brainliest \:$

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