Question

The refractive index
of a medium is found to vary with wavelength
as
What are the dimensions of A and B?

Answer 1

Answer:

Refractive index has no dimension. Thus if a + (b/lambda ²) = refractive index. Thn, a had no dimension and b has dimension of [ L²]

Answer 2

Answer:

A is dimensionless.

Dimension of B/ λ^2 =>

                     [B] / [L^2] = [M^0L^0T^0]

                                [B] = [M^0L^2T^0]

Or,                  [B] = [L^2]

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