Question

the refractive index of a prism material is 1.541.find its critical angle


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Answer 1

Answer:

$\sin(i) = \frac{1}{1.541} \\ \sin(i) = 0.65 \\ i = 40.46degree$

hope this will help you

Answer 2

The critical angle is 40.46°.

Given:

The refractive index of a prism material is 1.541.

To Find:

The critical angle.

Solution:

To find the critical angle we will follow the following steps:

As we know,

sine function of critical angles is inversely proportional to the refractive index.

So,

$sin(i) = \frac{1}{u}$

Here, 'i' is the critical angle and u is the refractive index.

Now,

According to the question:

Refractive index = 1.541

$sin(i) = \frac{1}{1.541} = 0.6489$

(Angle 40.46° = 0.6489)

So,

Angel 'i' or critical angle is 40.46°

Henceforth, The critical angle is 40.46°.

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