Question

the refractive index of an equilateral prism is 1.532.calculate the maximum deviation when it is immersed in water of refractive index 1.33.​

Answer 1

Solution :-

The angle of minimum deviation = 2i - A

• As for equilateral prism apex angle is 60

we know, r = A/2 = 60/2 = 30

Using the snell's law we get,

⇒ n1 sini = n2 sinr

⇒ 1.33sini = 1.53sin30

⇒ i = 35.11

• Minimum deviation δ = 2i−A

⇒ δ = 2 × 35.11 − 60

⇒ δ = 10.2

Final answer :-

Angle of minimum deviation δ = 10.2

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