Question

The refractive index of core and cladding material of an optical fiber are 1.54 and 1.5 respectively.calculate the numerical aperture of the optical fiber.​

Answer 1

Answer:

the value of the numerical aperture is 0.556

Step-by-step explanation:

hope it help you

Answer 2

given the index of core and cladding of an optical fiber, find its numerical aperture

Explanation:

1. Numerical Aperture (NA) of a fiber is defined as the sine of the largest angle an incident ray can have for total internal reflectance in the core.
2. For an Optical Fiber with index of core $n_1$ and index of cladding $n_2$ , its numerical aperture is given by ,   $NA=\sqrt{n_1^2-n_2^2}$  
3. here we have $n_1=1.54$  and $n_2=1.5$, hence we get ,                                                $NA=\sqrt{1.54^2-1.5^2} \\NA=0.348$