Question

The refractive index of denser medium with respect to rarer medium is 1.125. The difference between the velocities of light in the two media is 0.25 ×10^8 m/s. Find the velocities of light in the two media and their refractive indices​.​

Answer 1

Answer:

A

2.0×10

8

m/s; 2.25×10

8

m/s

Velocity of light in denser medium V

r

=

μ

2

ν

V

r

=

μ

2

3×10

8

Velocity of light in rarer medium V

d

=

μ

1

ν

V

d

=

μ

1

3×10

8

Given,

μ

1

μ

2

=1.125

μ

2

=1.125 μ

1

Given, V

r

−V

d

=0.25×10

8

⟹

μ

1

3×10

8

−

μ

2

3×10

8

=0.25×10

8

So, V

d

=2×10

8

m/s and V

r

=2.25×10

8

m/s

Answer 2

Answer:

Explanation:

Given refractive index of denser medium with respect to rarer medium =1.125

Also we know $V_{D.R} = \frac{V_R} {V_D} \\\\V_R = 1.125 V_D$

​  

Also we know, $V_R-V_D = 0.25 * 10^8 m/s$

Substituting the value of  $V_R$  we get

$V_D=2*10^8 m/s so V_R=2.25*10^8 m/s$

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