Question

the refractive index of methyl acetate is 1.3594 and its density is 0.928g/cm³.calculate the molar refraction​

Answer 1

Answer:

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Answer 2

The Molar Refraction of Methyl Acetate is 17.54

Explanation:

Given:

Refractive index of Methyl Acetate = 1.3594

Density of Methyl Acetate = 0.928 g/cm³

To find out:

The molar refraction

Solution:

According to Lorentz-Lorenz equation, the molar refraction is given by

$R=(\frac{n^2-1}{n^2+2})\frac{M}{r}$

Here

$n=1.3594$

$r=0.928$ g/cm³

Molar mass of Methyl Acetate

$M=74$

Thus,

$R=(\frac{1.3594^2-1}{1.3594^2+2})\times\frac{74}{0.928}$

$\implies R=17.54$ cm³

Hope this answer is helpful.

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