Question

the refractive index of the material of a prism is 1.3 and the angle of the prism is 60°.find the angle of minimum deviation of the material of the prism.​

Answer 1

Answer:19.46°

Explanation:n=[sin(A+ζmin)/2]/sinA/2

ζmin=min. Deviation

1.3=[sin(60+ζmin)]/sin (60/2)

1.3=[sin(60+ζmin)]/sin 30

1.3=2sin(60+ζmin)

0.65=sin(60+ζmin)

sin^-1(0.65)=(60+ζmin)

40.54=(60+ζmin)

ζmin=60-40.54

=19.46°