Question

The refractive index of the material of an equi-double convex lens is 1.5. Prove that the focal length is equal to the radius of curvature.

Answer 1

Answer:

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Answer 2

Given,

Refractive index of the material=1.5

To Find,

Focal length of the of lens = Radius of curvature

Solution,

We will use lens maker formula to prove this,

1/f=((μ1/μ2)-1 )(1/R1-1/R2)

⇒1/f=((1.5/1)-1)((1/R-(-1/R))

⇒1/f=1/2×2/R

⇒1/f=1/R

Thant means, R=f

Hence, it is proved that focal length of the lens is equal to the radius of curvature.