The refractive index of water is 4/3. Obtain the value of semi vertical angle of the cone within which the entire outside view would be confined for a fish under water. Draw an appropriate ray diagram.
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Explanation:
=> The angle of cone from which fish can see the entire outside view is 2c.
∴ θ = 2c
where, sin C = μ_a/μ_w
sin C = 1 / 4/3
C = sin⁻¹ 3/4
=> Thus, angle of cone,
θ = 2c
= 2 sin⁻¹ 3/4
= 2 sin⁻¹ (0.75)
= 2 * 48.7
= 97.4°
Thus, the angle of cone from which fish can see the entire outside view is 97.4°.
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Answer:The angle of cone from which fish can see the entire outside view is 2c.
∴ θ = 2c
where, sin C = μ_a/μ_w
sin C = 1 / 4/3
C = sin⁻¹ 3/4
=> Thus, angle of cone,
θ = 2c
= 2 sin⁻¹ 3/4
= 2 sin⁻¹ (0.75)
= 2 × 48.7
= 97.4° Ans...
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